If a magnet of length 10 cm and pole strength 40 Am is placed at an angle of 45o in an uniform induction field of intensity 2 x 10-4 T, the couple acting on it is

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0.5656 x 10-4 Nm

0.5656 x 10-3 Nm

0.656 x 10-4 Nm

0.656 x 10-5 Nm

answer is B.

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Detailed Solution

τ=MB sin θ = (mL) B sin θ=(40 x 10 x 10-2)x 2x 10-4sin45o= 0.565 x 10-3N m

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