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If a magnet of length 10 cm and pole strength 40 Am is placed at an angle of 45o in an uniform induction field of intensity 2 x 10-4 T, the couple acting on it is

0.5656 x 10-4 Nm
0.5656 x 10-3 Nm
0.656 x 10-4 Nm
0.656 x 10-5 Nm

detailed solution

Correct option is B

τ=MB sin θ = (mL) B sin θ=(40 x 10 x 10-2)x 2x 10-4sin45o= 0.565 x 10-3N m

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