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If a magnet of length 10 cm and pole strength 40 Am is placed at an angle of in an uniform induction field of intensity , the couple acting on it is
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Correct option is B
τ=MB sin θ = (mL) B sin θ=(40 x 10 x 10-2)x 2x 10-4sin45o= 0.565 x 10-3N m
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