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Questions  

If a magnet is suspended at an angle of 300 to the magnetic meridian the dip needle makes an angle of 600 with the horizontal. The real dip is

a
tan−13/2
b
tan−13
c
tan−13/2
d
tan−12/3

detailed solution

Correct option is A

tanθ=Bv/BH …………………..(1)[real dip is θ  ]In the plane situated at 300 with the magnetic meridian the horizontal component of the earth’s magnetic field will be BHcos300  and the vertical component will be  Bv. The angle of dip in this plane is    tan600=BvBHcos300tan600.cos300=BvBH From equation (1)⇒tanθ=tan600.cos300⇒tanθ=3.32 ⇒θ=tan−13/2

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