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If a magnet is suspended at an angle of to the magnetic meridian the dip needle makes an angle of with the horizontal. The real dip is
detailed solution
Correct option is A
tanθ=Bv/BH …………………..(1)[real dip is θ ]In the plane situated at 300 with the magnetic meridian the horizontal component of the earth’s magnetic field will be BHcos300 and the vertical component will be Bv. The angle of dip in this plane is tan600=BvBHcos300tan600.cos300=BvBH From equation (1)⇒tanθ=tan600.cos300⇒tanθ=3.32 ⇒θ=tan−13/2Talk to our academic expert!
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