If a magnet is suspended at an angle of 300 to the magnetic meridian, the dip needle makes an angle of 600 with the horizontal. The real dip is
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a
tan−1(3/2)
b
tan−1(2/3)
c
tan−13/2
d
tan−12/3
answer is A.
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Detailed Solution
tanθ=BV/BH [real dip is θ ]…………………(1)In the place situated at 300 with the magnetic meridian, the horizontal component of the earth’s magnetic field will be BHcos300 while the vertical component will be Bv. The angle of dip in this place istan60o=BvBHcos30o ⇒tan60o.cos30o=BvBHFrom equation (1), ⇒tanθ=3.32 ⇒tanθ=32⇒θ=tan−132 .