If a magnet is suspended at an angle of 30o to the magnetic meridian and the dip needle makes an angle of 45o with horizontal, then the real angle of dip is
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a
tan-132
b
tan-13
c
tan-132
d
tan-123
answer is A.
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Detailed Solution
∴tan δ=BVBH-(i) where δ is the true angle of dip∴tan 45o=BVBH cos30o-(ii)Dividing (i) and (ii), we getδ=tan-132
If a magnet is suspended at an angle of 30o to the magnetic meridian and the dip needle makes an angle of 45o with horizontal, then the real angle of dip is