Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

If a magnet is suspended at an angle of 30o to the magnetic meridian and the dip needle makes an angle of 45o with horizontal, then the real angle of dip is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

tan-132

b

tan-13

c

tan-132

d

tan-123

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

∴tan δ=BVBH-(i)  where δ is the true angle of dip∴tan 45o=BVBH cos30o-(ii)Dividing (i) and (ii), we getδ=tan-132
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring
If a magnet is suspended at an angle of 30o to the magnetic meridian and the dip needle makes an angle of 45o with horizontal, then the real angle of dip is