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Questions  

If a magnet is suspended at an angle of 30o to the magnetic meridian and the dip needle makes an angle of 45o with horizontal, then the real angle of dip is

a
tan-132
b
tan-13
c
tan-132
d
tan-123

detailed solution

Correct option is A

∴tan δ=BVBH-(i)  where δ is the true angle of dip∴tan 45o=BVBH cos30o-(ii)Dividing (i) and (ii), we getδ=tan-132

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The values of the apparent angles of dip in two planes at right angles to each other are 30o and 45o. Then the true value of the angle of dip at the place is 


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