If the magnetic field at P can be written as K tanα2, then K is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
μ0I4πd
b
μ0I2πd
c
μ0Iπd
d
2μ0Iπd
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let us compute the magnetic field due to any one segment: B=μ0i4π(dsinα)cos0°+cos180°-α =μ0I4π(dsinα)(1-cosα)=μ0I4πdtanα2 Resultant field will be Bnet =2B=μ0I2πdtanα2⇒K=μ0I2πd