Q.

If the magnetic field at P can be written as K tanα2, then K is

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a

μ0I4πd

b

μ0I2πd

c

μ0Iπd

d

2μ0Iπd

answer is B.

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Detailed Solution

Let us compute the magnetic field due to any one segment: B=μ0i4π(dsinα)cos0°+cos180°-α =μ0I4π(dsinα)(1-cosα)=μ0I4πdtanα2 Resultant field will be Bnet =2B=μ0I2πdtanα2⇒K=μ0I2πd
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