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Questions  

If the magnetic field in a plane electromagnetic wave is given by B=3×108sin1.6×103x+48×1010tj^T; then what will be the expression for the electric field?

a
E→=9sin1.6×103x+48×1010tk^V/m
b
E→=3×10−8sin1.6×103x+48×1010ti^V/m
c
E→=3×10−8sin1.6×103x+48×1010tj^V/m
d
E→=60sin1.6×103x+48×1010tk^V/m

detailed solution

Correct option is A

We know that, E0B0=C        speed of light in vacuumAmplitude of electric field,  E0=B0C=3×10−8×3×108 =9N/COnly option 1 matches.                                                                                                                        when an electro magnetic wave passes through a medium electric field vector ,magnetic field vector and direction of propagation of the wave are in mutually perpendicular directions.E=E0sin kx+ωt

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