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If the magnetic field of a plane electromagnetic wave is given by B=5×106sin[0.6×102x+0.5×1010t] then the speed of the wave is

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a
0.83×107m/s
b
0.83×108m/s
c
5.24×108m/s
d
5.24×109m/s

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detailed solution

Correct option is B

Given equation is  B=5×10-6sin(0.6×102x+0.5×1010t)TComparing the given equation with the equation of  B=B0sin(Kx+ωt)Then K=0.6×102m−1 and  ω=0.5×1010rad/sSpeed of the wave is  V=ωK=0.5×10100.6×102=56×108 ⇒V=0.83×108m/s


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