If the magnetic field of a plane electromagnetic wave is given by B=5×10−6sin[0.6×102x+0.5×1010t] then the speed of the wave is

Given equation is  B=5×10-6sin(0.6×102x+0.5×1010t)TComparing the given equation with the equation of  B=B0sin(Kx+ωt)Then K=0.6×102m−1 and  ω=0.5×1010rad/sSpeed of the wave is  V=ωK=0.5×10100.6×102=56×108 ⇒V=0.83×108m/s