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If the magnetic field of a plane electromagnetic wave is given by  B=1×106sin[0.4×102x+0.3×1010t]T. Then the speed of the wave is

a
0.75×107m/s
b
0.75×108m/s
c
1.33×109m/s
d
1.33×107m/s

detailed solution

Correct option is B

Given equation is  B=1×10−6sin[0.4×102x+0.3×1010t]TComparing the given equation with the equation of  B=B0sin[Kx+ωt]Then  K=0.4×102m−1  &ω=0.3×1010rad/sSpeed of the wave is  V=ωK=0.30.4×1010102=34×108⇒V=0.75×108m/s

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