Q.

If the magnitude of scalar and vector products of two vectors are 6 and 63  respectively, then the angle between two vectors is

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a

150

b

300

c

600

d

750

answer is C.

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Detailed Solution

A→.B→=AB cosθ=6 and  |A→×B→|=ABsinθ=63 ∴    AB sinθAB cosθ=636=3 or         tanθ=3   and  θ=600
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