Q.
If a man increase his speed by 2 m/s, his K.E. is doubled, the original speed of the man is
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a
(1+22) m/s
b
4 m/s
c
(2+22) m/s
d
(2+2) m/s
answer is C.
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Detailed Solution
Initial kinetic energy E=12mv2 …(i)Final kinetic energy 2E=12m(v+2)2 …(ii) by solving equation (i) and (ii) we get v=(2+22) m/s
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