Q.

If a man increase his speed by 2 m/s, his K.E. is doubled, the original speed of the man is

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a

(1+22) m/s

b

4 m/s

c

(2+22) m/s

d

(2+2) m/s

answer is C.

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Detailed Solution

Initial kinetic energy E=12mv2                …(i)Final kinetic energy 2E=12m(v+2)2      …(ii) by solving equation (i) and (ii) we get  v=(2+22) m​/​s
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