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If the mass of the electron $(9 \times 10^{- 31} k g)$ is taken as unit of mass, the radius of the second Bohr orbit $2.0 \times 10^{- 10}$ as unit of length and 500 Newton as the unit of force, then the unit of time in the new system would be

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6×10–22s

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detailed solution

Correct option is A

F=MLT-2 T-2=MLF=9×10-31×2.0×10-10500=36×10-44 T=6×10-22s

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If the mass of the electron (9×10−31kg) is taken as unit of mass, the radius of the second Bohr orbit 2.0×10−10 as unit of length and 500 Newton as the unit of force, then the unit of time in the new system would be

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Ready to Test Your Skills?

free study material

If the mass of the electron $(9 \times 10^{- 31} k g)$ is taken as unit of mass, the radius of the second Bohr orbit $2.0 \times 10^{- 10}$ as unit of length and 500 Newton as the unit of force, then the unit of time in the new system would be