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Q.

If mass of  molecule X  is 4 times that of hydrogen. Then mean velocity of X  is

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a

2 times the mean velocity of H2

b

12  times the mean velocity of H2

c

4 times the mean velocity of H2

d

Equal to the mean velocity of H2

answer is B.

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Detailed Solution

Vmean= 8KTπmm is mass of 1 moleculeVmean= ∝    1m∴     VmeanXVmeanH2=    m4m  = 12
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