First slide

Mass Energy equivalence

Question

If mass of $U^{235} = 235.12142 a m u,$ mass of $U^{236} = 236.1205 a m u$ and mass of neutron = 1.008665 amu, then the energy required to remove one neutron from the nucleus $U^{236} i s a b o u t$

Moderate

A

75 MeV
B

9 MeV
C

1 eV
D

Zero

Solution

(2)
Energy required
= Final rest mass energy - Initial rest mass energy
= (235.12142 + 1.008665) - 236.1205] x 931 MeV
= 0.009585 x 931 MeV
$= 8.92 M e V ≃ 9 M e V .$

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