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Q.

If mass of U235 =235.12142  amu, mass of U236 =236.1205  amu and mass of neutron = 1.008665 amu, then the energy required to remove one neutron from the nucleus U236  is  about

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a

75 MeV

b

9 MeV

c

1 eV

d

Zero

answer is B.

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Detailed Solution

(2)Energy required= Final rest mass energy - Initial rest mass energy= (235.12142 + 1.008665) - 236.1205] x 931 MeV= 0.009585 x 931 MeV=8.92   MeV  ≃   9 MeV.
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