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Questions  

If the maximum acceleration of a SHM is ‘a’ and the maximum velocity is ‘b’ , then amplitude of vibration is

a
b2a
b
a2b
c
b2a
d
a2b

detailed solution

Correct option is C

acceleration maximum =-w2A ⇒a=-w2A-------(1) maximum velocity        =  wA    ⇒b=  wA⇒b2=w2A2--(2) divide the above equations  A=b2a

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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