First slide

Simple harmonic motion

Question

If the maximum acceleration of a SHM is ‘a’ and the maximum velocity is ‘b’ , then amplitude of vibration is

Moderate

A

$b^{2} a$
B

$a^{2} b$
C

$\frac{b^{2}}{a}$
D

$\frac{a^{2}}{b}$

Solution

$a c c e l e r a t i o n m a x i m u m = - w^{2} A \Rightarrow a = - w^{2} A - - - - - - - (1) m a x i m u m v e l o c i t y = w A \Rightarrow b = w A \Rightarrow b^{2} = w^{2} A^{2} - - (2) d i v i d e t h e a b o v e e q u a t i o n s A = \frac{b^{2}}{a}$

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