Questions
If the mean free path is doubled, then the pressure of the gas at constant temperature becomes
detailed solution
Correct option is B
λ=12kTπd2P α 1P (at constant temperature).λ α 1P λ1λ2=P2P1=2PP λ2=λ12Talk to our academic expert!
Similar Questions
Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1 and 2 . The gases may be considered under identical conditions of temperature, pressure and volume.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
