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Q.

If 2 mol of an ideal monatomic gas at temperature T0 are mixed with 4 mol of another ideal monatomic gas at temperature 2T0, then the temperature of the mixture is

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a

53T0

b

32T0

c

43T0

d

54T0

answer is A.

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Detailed Solution

Let T be the temperature of the mixture.Then U=U1+U2or f2(n1+n2)RT=f2(n1)(R)(T0)+f2(n)(R)(2T0)or (2+4)T=2T0+8T0     (∵n1=2,  n2=4)∴ T=53T0
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