If 2 mol of an ideal monoatomic gas at temperature T0 are mixed with 4 mol of another ideal monoatomic gas at temperature 2T0, then the temperature of the mixture is

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53T0

32T0

43T0

54T0

answer is A.

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Detailed Solution

Let T be the temperature of the mixture.Then U=U1+U2or f2n1+n2RT=f2n1(R)T0+f2(n2)(R)2T0or (2+4)T=2T0+8T0 ∵ n1=2, n2=4∴ T=53T0

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