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Q.

If the moment of inertia of a rod of mass M and length L about an axis passing through its centre of mass and perpendicular to its length is (ML2/12), then moment of inertia of the same rod about an axis passing through one of its ends and parallel to the given axis will be:

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a

(ML2/12)

b

(ML2/6)

c

(ML2/3)

d

(13/12)ML2

answer is C.

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I=ICM+Md2=ML212+ML22=ML23
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