Question

If the momentum of a body is increased by 100%, then the percentage increase in the kinetic energy is

Moderate

Solution

$E = \frac{P^{2}}{2 m} \Rightarrow E_{2} = E_{1} {(\frac{P_{2}}{P_{1}})}^{2} = E_{1} {(\frac{2 P}{P})}^{2}$
$\Rightarrow E_{2} = 4 E = E + 3 E = E + 300 % of E$

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