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Q.

If momentum of a certain body is increased by 50%then increase in the K.E. of the body will be

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a

25%

b

50%

c

100%

d

125%

answer is D.

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Detailed Solution

p=(2mE)  or  E∝p2 ∴ E2E1=p22p12  or  E2E1−1=p22p12−1  or E2−E1E1×100=p22−p12p12×100 % increase =(150)2−(100)2(100)2×100 =(150+100)(150−100)100=125%
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