If momentum is increased by 20%, then K.E. increases by __%
E=P22m. If m is constant then E∝P2⇒E2E1=P2P12=1.2PP2=1.44⇒E2=1.44E1=E1+0.44E1E2=E1+44% of E1i.e. the kinetic energy will increase by 44%