If n drops, each of capacitance C, coalesce to form a single big drop, then the ratio of the energy stored in big drop to that in each small drop will be
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a
n :1
b
n1/3:1
c
n5/3:1
d
n2:1
answer is B.
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Detailed Solution
We know that, capacitance a radius .If r is the radius of each drop, then the radius fi of big drop will be R=r×(n)1/3We also know that, energy ∞ capacitance ∴ Energy stored in big drop Energy stored in small drop =n1/3