First slide

Capacitance

Question

If n drops, each of capacitance C, coalesce to form a single big drop, then the ratio of the energy stored in big drop to that in each small drop will be

Easy

A

n :1
B

$n^{1 / 3} : 1$
C

$n^{5 / 3} : 1$
D

$n^{2} : 1$

Solution

We know that, capacitance a radius .If r is the radius of each drop, then the radius fi of big drop will be $R = r \times (n)^{1 / 3}$
We also know that, energy $\infty$ capacitance
$∴ \frac{Energy stored in big drop}{Energy stored in small drop} = n^{1 / 3}$

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