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If $N_{1} = N_{0} e^{- λ t_{1}}$ then the number of atoms decayed during time interval from $t_{1}$ to $t_{2}$ $(t_{2} > t_{1})$ will be

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Nt1−Nt2=N0[e−λt1−e−λt2]

Nt2−Nt1=N0[e−λt2−eλt1]

Nt2−Nt1=N0[e−λt2−e−λt1]

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detailed solution

Correct option is A

Nt1=N0e−λt1 Nt2=N0e−λt2 No. of atoms decayed during time interval t1 to t2 is=Nt1−Nt2=N0[e−λt1−e−λt2]

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If N1=N0e−λt1 then the number of atoms decayed during time interval from t1 to t2 (t2>t1) will be

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If $N_{1} = N_{0} e^{- λ t_{1}}$ then the number of atoms decayed during time interval from $t_{1}$ to $t_{2}$ $(t_{2} > t_{1})$ will be