If in nature there may not be an element for which the principal quantum number n > 4, then the total possible number of elements will be
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a
60
b
32
c
4
d
64
answer is A.
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Detailed Solution
For n = 1, maximum number of states = 2n2 = 2 and for n = 2, 3, 4, maximum number of states would be 8, 18, 32 respectively, Hence number of possible elements =2+8+18+32=60