Q.

If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is

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a

1.25×107

b

2.25×107

c

3.25×107

d

0.25×107

answer is A.

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Detailed Solution

E=Δmc2=0.5×10−3×3×1082=4.5×1013j ⇒E=4.5×10133.6×106=1.25×107kWH
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