If an object starts from rest and covers angle of 60 rad in 10s in circular motion, then magnitude of its angular acceleration will be [JIPMER 2019]

Given, initial angular velocity of object, ω0=0Angular displacement,  θ=60radand    Δt=10sFrom equation of rotational motion,  θ=ω0t+12αt260=0×t+12×α×102⇒ α=6050⇒α=1.2rads−2