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If an object starts from rest and covers angle of 60 rad in 10s in circular motion, then magnitude of its angular acceleration will be [JIPMER 2019]

a
1.2 rad s-2
b
1.5 rad s-2
c
2 rad s-2
d
2.5 rad s-2

detailed solution

Correct option is A

Given, initial angular velocity of object, ω0=0Angular displacement,  θ=60radand    Δt=10sFrom equation of rotational motion,  θ=ω0t+12αt260=0×t+12×α×102⇒ α=6050⇒α=1.2rads−2

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