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Q.

If one end of a wire is fixed with a rigid support and the other end is stretched by a force of 10N, then the increase in length is 0.5 mm. The ratio of the energy of the wireand the work done in displacing it through 1.5 mm by the weight is

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a

13

b

14

c

12

d

1

answer is C.

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Detailed Solution

Energy stored in stretching a wireU=12Fl=12×10×0.5×10−3=2.5×10−3JWork done to displace it through 1.5 mmW=F×l=10×0.5×10−3=5×10−3JThe ratio of energy and work =UW=2.5×10-35×10-3=1:2
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If one end of a wire is fixed with a rigid support and the other end is stretched by a force of 10N, then the increase in length is 0.5 mm. The ratio of the energy of the wireand the work done in displacing it through 1.5 mm by the weight is