If one mole of a mono atomic gas γ=53 , is mixed with one mole of diatomic gas γ=75, what is the value of γ for the mixture.
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a
32
b
52
c
65
d
85
answer is A.
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Detailed Solution
specific heat of mixture of gases at constant volume is Cvmixture=n1CV1+n2Cv2n1+n2 Cvmixture=(1)32R+(1)52R2=2RAverage CPmixture= Cvmixture+R ⇒CPmixture=2R+R ⇒CPmixture=3R ∴for mixture of gases γ=CPmixture Cvmixture ⇒γmix=3R2R ⇒γmix=32