If one wants to remove all the mass of earth to infinity in order to break it up completely. The amount of energy that needs to supplied will be $$x5GM2R$$ where x $$is______$$ (Round$$ off to the Nearest $$Integer)(M$$ is the mass of earth, R is the radius of earth and G is the gravitational $$constant)

E−Uf−$$UiE=0$$−$$35GMe2Re=35GMe2Re$$ (Self$$−$$energy) So, $$x=3$$

Gravitational potential and potential energy

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Question

If one wants to remove all the mass of earth to infinity in order to break it up completely. The amount of energy that needs to supplied will be $\frac{x}{5} \frac{G M^{2}}{R}$ where x is______ (Round off to the Nearest Integer)
(M is the mass of earth, R is the radius of earth and G is the gravitational constant)

Moderate

Solution

$E - U_{f} - U_{i}$
$E = 0 - (\frac{3}{5} \frac{G M_{e}^{2}}{R_{e}}) = \frac{3}{5} \frac{G M_{e}^{2}}{R_{e}} (S e l f - e n e r g y) S o, x = 3$

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Gravitational potential and potential energy

Remember concepts with our Masterclasses.

If one wants to remove all the mass of earth to infinity in order to break it up completely. The amount of energy that needs to supplied will be x5GM2R where x is______ (Round off to the Nearest Integer)(M is the mass of earth, R is the radius of earth and G is the gravitational constant)

E−Uf−UiE=0−35GMe2Re=35GMe2Re (Self−energy) So, x=3

Ready to Test Your Skills?

free study material

$E - U_{f} - U_{i}$
$E = 0 - (\frac{3}{5} \frac{G M_{e}^{2}}{R_{e}}) = \frac{3}{5} \frac{G M_{e}^{2}}{R_{e}} (S e l f - e n e r g y) S o, x = 3$