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Questions  

If P=3i^+5j^+2k^  , Q=5i^j^+4k^  and R=4i^+2j^+3k^ are coplanar, then:

a
(P→×Q→).R→=0
b
(P→.Q→)×R→=0
c
P→×Q→×R→=0
d
(P→.Q→).R→=0

detailed solution

Correct option is A

The scalar triple product P→.(Q→×R→)=(P→×Q→).R→  for three coplanar vectors is always zero, as it represents the volume of parallelepiped formed with three adjacent sides as the vectors P→,Q→  and R→ . Here P→×Q→=(3i^+5j^+2k^)×(5i^−j^+4k^) =| i^     j^     k^  3     5     2  5   −1    4 | =i^(20+2)−j^(12−10)+k^(−3−25) =22i^−2j^−28k^ (P→×Q→).R→=(22i^−2j^−28k^).(4i+2j^+3k^) =88−4−84=zero .

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