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If $\vec{P} \cdot \vec{Q} = P Q$ , then angle between $\vec{P}$ and $\vec{Q}$ is

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Correct option is A

cos⁡θ=P→⋅Q→PQ=1 ∴ θ=0∘

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If P→⋅Q→=PQ, then angle between P→ and Q→ is

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If $\vec{P} \cdot \vec{Q} = P Q$ , then angle between $\vec{P}$ and $\vec{Q}$ is