First slide

Scalars and Vectors

Question

If $\vec{P} \cdot \vec{Q} = P Q$ , then angle between $\vec{P}$ and $\vec{Q}$ is

Easy

A

0⁰
B

30⁰
C

45⁰
D

60⁰

Solution

$\cos θ = \frac{\vec{P} \cdot \vec{Q}}{P Q} = 1 ∴ θ = 0^{\circ}$

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