First slide

Second law

Question

If P_x=2 sin t and p_y = 2cost, then the angle between linear momentum p and force F will be

Easy

A

30°
B

45°
C

60°
D

90°

Solution

Given that, $p_{x} = 2 \sin t and p_{y} = 2 \cos t$
$\begin{array}{l} ∴ p = p_{x} i + p_{y} j \\ = (2 \sin t) i + (2 \cos t) j . . . . (1) \end{array}$
We know that P = dp/dt
So, $F = (2 \cos t) i - (2 \sin t) j . . . . (2)$
from eqs. (1) and (2), p.F = 0
So, the angle between p and F is 90°

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