If Px=2 sin t and py = 2cost, then the angle between linear momentum p and force F will be

Given that, px=2sin⁡t and py=2cos⁡t∴p=pxi+pyj=(2sin⁡t)i+(2cos⁡t)j....(1)We know that P = dp/dtSo, F=(2cos⁡t)i−(2sin⁡t)j....(2)from eqs. (1) and (2), p.F = 0So, the angle between p and F is 90°