If a particle of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2 × 104 ms−1 in a uniform magnetic field, then the value of the magnetic induction is g=10 m s−2

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Zero

10 T

20 T

200 T

answer is C.

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Detailed Solution

Particle will move with uniform velocity when its acceleration is zero.i.e., Fm =mg ⇒ mg=qvB⇒ B=mgqv = 0.6 × 10−3× 1025 × 10−9× 1.2 × 10−4=20 T

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