First slide

Force on a charged particle moving in a magnetic field

Question

If a particle of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity $1 .2 \times 10^{4} {ms}^{- 1}$ in a uniform magnetic field, then the value of the magnetic induction is $(g = 10 m s^{- 2})$

Moderate

A

Zero
B

10 T
C

20 T
D

200 T

Solution

Particle will move with uniform velocity when its acceleration is zero.
$\begin{array}{l} i . e ., |F_{m}| = mg \Rightarrow mg = qvB \\ \Rightarrow B = \frac{mg}{qv} = \frac{0 .6 \times 10^{- 3} \times 10}{25 \times 10^{- 9} \times 1 .2 \times 10^{- 4}} = 20 T \end{array}$

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