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Q.

If a particle of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity 1.2 ×  104 ms−1 in a uniform magnetic field, then the value of the magnetic induction is g=10  m  s−2

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a

Zero

b

10 T

c

20 T

d

200 T

answer is C.

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Detailed Solution

Particle will move with uniform velocity when its acceleration is zero.i.e.,  Fm =mg ⇒  mg=qvB⇒  B=mgqv = 0.6  ×  10−3×  1025  ×  10−9× 1.2  ×  10−4=20  T
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