If a particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in fig. Its angular momentum with respect to origin at any time t will be
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a
mvbk^
b
-mvb k^
c
mvb i^
d
mv i^
answer is B.
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Detailed Solution
We know that, Angular momentumL→.= r→xP→ in terms of component becomesAs motion is in x-y plane (z = 0 and Pz = 0), as L→.= k^ (xpy - ypx)Here x = vt, y = b, px= mv and py = 0∴L→= k^ [vt×0-b mv] = - mvb k^