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If a particle of mass m is moving with constant velocity v parallel to x-axis in x-y plane as shown in fig. Its angular momentum with respect to origin at any time t will be
detailed solution
Correct option is B
We know that, Angular momentumL→.= r→xP→ in terms of component becomesAs motion is in x-y plane (z = 0 and Pz = 0), as L→.= k^ (xpy - ypx)Here x = vt, y = b, px= mv and py = 0∴L→= k^ [vt×0-b mv] = - mvb k^Talk to our academic expert!
Similar Questions
A particle of mass m = 5 units is moving with a uniform speed , units in the XOY plane along the line y = x + 4. The magnitude of the angular momentum of the Particle about the origin is
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