Questions
If a particle of mass m slides back and forth between two smooth planes as shown in figure, the correct statement is
detailed solution
Correct option is D
The particle of mass m is at rest on top of the inclined plane. Let it start sliding down and attain a speed of V at the bottom of the inclined plane.According to the law of conservation of energy, mgh=12mv 2 .On simplifying this we get v=2gh……………………..(1)The acceleration of the particle down the inclined plane is obtained by resolving g in the direction of the plane of inclination.We get the acceleration of the particle as gsinθ . Using this we find the time taken to go down the inclined plane using equations of motion. v=u+at , Substituting v=2gh, u=0 and a=gsinθ,We get 2gh=u+gsinθ t,Therefore, 2ghgsinθ =t.= time of descent The total time taken=time period of motion will be four times the time taken to reach the ground,Hence, time period of oscillation =42ghgsinθ .and frequency of oscillation = gsin2θ32hTalk to our academic expert!
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A body executes S.H.M. under the action of a force F1 with a time period 7/6 seconds. If the force is changed to F2 it executes S.H.M. with time period 7/8 seconds. If both the forces F1 and F2 act simultaneously in the same direction on the body, then its time period in seconds is
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