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Questions  

If the particle is moving along a straight line given by the relation x = 2 - 3t + 4t3 where x is in cms., and t in sec. Its average velocity during the third sec is ?

a
73 cm/s
b
80 cm/s
c
85 cm/s
d
90 cm/s

detailed solution

Correct option is A

x = 2 - 3t + 4t3t = 2 ⇒ x2 = 2 - 6 + 32 = 28mt = 3 ⇒ x3= 2 - 9 + 108 = 101m vavg=x3-x23-2= 101-281=73cm/s

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