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Questions  

If a particle under S.H.M. has time period 0.1 sec and amplitude 2×10-3m . It has maximum velocity

a
π25 m​/​s
b
π26 m​/​s
c
π30 m​/​s
d
None of these

detailed solution

Correct option is A

vmax=aω=a×2πT=2×10−3×2π0.1=π25m/s

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A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 3.92×103m . What must be the least period of these oscillations, so that the object is not detached from the platform 


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