Q.
If a particle under S.H.M. has time period 0.1 sec and amplitude 2×10-3m . It has maximum velocity
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a
π25 m/s
b
π26 m/s
c
π30 m/s
d
None of these
answer is A.
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Detailed Solution
vmax=aω=a×2πT=2×10−3×2π0.1=π25m/s
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