First slide

Alternating current and voltage

Question

If the peak value of an alternating current is 6 A, then r.m.s. value of current will be

Easy

A

3 A
B

$3 \sqrt{3} A$
C

$3 \sqrt{2} A$
D

$2 \sqrt{3} A$

Solution

$i_{r \cdot m . s} = \frac{6}{\sqrt{2}} = 3 \sqrt{2} A$

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