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If the percentage of modulation is 50 % then the useful power in the AM wave is

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a

44 %

b

33 %

c

22 %

d

11 %

answer is D.

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Detailed Solution

Given : m = 0.50 = 12 We know that, PTPC=1+m22 and PT = PC + PS ∴ useful power = PSPT=m22+m2 =1222+122=142+14=1494=19 = 0.11 In percentage , 11 %

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