If potential (in volts) in a region is expressed as V(x,y,x)=6xy−y+2yz , the electric field (in N/C) at point (1, 1, 1) is
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a
−(2i^+3j^+k^)
b
−(6i^+9j^+k^)
c
−(3i^+5j^+3k^)
d
−(6i^+7j^+2k^)
answer is D.
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Detailed Solution
The electric field E→ and potential v in a region are related as E→=−[∂V∂xi^+∂V∂yj^+∂V∂zk^] Here, V(x,y,z)=6xy−y+2yz ∴E→=−[∂∂x(6xy−y+2yz)i^+∂∂y(6xy−y+2yz)j^+∂∂y(6xy−y+2yz)k^] =[(6y)i^+(6x−1+2z)k^+(2y)k^] At point (1,1,1),E→=[(6(1)i^+6(1)−1+2(1))j^+(2(1))k^] =−(6i^+7j^+2k^) .