If potential (in volts) in a region is expressed as V(x, y, z) = 6 x y - y + 2yz , the electric field (in N/C) at point (1,1,0) is
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a
-(2i^+3j^+k^)
b
-(6i^+9j^+k^)
c
-(3i^+5j^+3k^)
d
-(6i^+5j^+2k^)
answer is D.
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Detailed Solution
The electric field E→ and potential V in a region are related asE→=-∂V∂xi^+∂V∂yj^+∂V∂zk^ Here, V(x,y,z)=6xy-y+2yz∴ E→=-∂∂x(6xy-y+2yz)i^+∂∂y(6xy-y+2yz)j^+∂∂z(6xy-y+2yz)k^=-[(6y)i^+(6x-1+2z)k^+(2y)k^] At point (1,1,0)E→=-[(6(1))i^+(6(1)-1+2(0))j^+(2(1))k^]=-(6i^+5j^+2k^)