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Questions  

If power dissipated in 1Ω  resistor is 16 watt., total power consumed by the network between A and B is ______

a
70 W
b
60 W
c
80 W
d
50 W

detailed solution

Correct option is A

i12  ×  1=16  ⇒  i1=4A.                  ∴   i2  =  4× 14A=1 Amp. ∴Total power consumed =16  +  12 ×  4+4+12  ×  2 W  =70  W.

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