Q.

If power dissipated in 1 Ω  resistor is 16 watt., total power consumed by the network between A and B is ______

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a

70 W

b

60 W

c

80 W

d

50 W

answer is A.

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Detailed Solution

i12  ×  1=16  ⇒  i1=4A.                  ∴   i2  =  4× 14A=1 Amp. ∴Total power consumed =16  +  12 ×  4+4+12  ×  2 W  =70  W.
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If power dissipated in 1 Ω  resistor is 16 watt., total power consumed by the network between A and B is ______