If power dissipated in 1 Ω resistor is 16 watt., total power consumed by the network between A and B is ______
70 W
60 W
80 W
50 W
i12 × 1=16 ⇒ i1=4A. ∴ i2 = 4× 14A=1 Amp. ∴Total power consumed =16 + 12 × 4+4+12 × 2 W =70 W.