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If power dissipated in 1 Ω resistor is 16 watt., total power consumed by the network between A and B is ______

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a

70 W

b

60 W

c

80 W

d

50 W

answer is A.

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Detailed Solution

i12 × 1=16 ⇒ i1=4A. ∴ i2 = 4× 14A=1 Amp. ∴Total power consumed =16 + 12 × 4+4+12 × 2 W =70 W.

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If power dissipated in 1 Ω resistor is 16 watt., total power consumed by the network between A and B is ______