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If power factor is 1/2 in a series RL circuit $R = 100 Ω$ . ac mains is used then L is

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3π Henry

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π3 Henry

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detailed solution

Correct option is A

cosφ=12⇒φ=60o tan60o=ωLR⇒L=3πH

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If power factor is 1/2 in a series RL circuit R=100 Ω. ac mains is used then L is

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If power factor is 1/2 in a series RL circuit $R = 100 Ω$ . ac mains is used then L is