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If pressure of CO₂ (real gas) in a container is given by $P = \frac{RT}{2 V - b} - \frac{a}{4 b^{2}}$ then mass of the gas in container is

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11 gm

22 gm

33 gm

44 gm

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detailed solution

Correct option is B

Vander wall's gas equation for μ mole of real gasP+μ2aV2(V−μb)=μRT⇒P=μRTV−μb−μ2aV2on comparing the given equation with this standard equation we get μ=12. Hence μ=mM ⇒ mass of gas m=μm=12×44=22gm.

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