If pressure of CO2 (real gas) in a container is given by P=RT2V−b−a4b2 then mass of the gas in container is
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a
11 gm
b
22 gm
c
33 gm
d
44 gm
answer is B.
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Detailed Solution
Vander wall's gas equation for μ mole of real gasP+μ2aV2(V−μb)=μRT⇒P=μRTV−μb−μ2aV2on comparing the given equation with this standard equation we get μ=12. Hence μ=mM ⇒ mass of gas m=μm=12×44=22gm.