Q.

If a pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 10C, the initial temperature must be

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a

250K

b

2500C

c

2500 K

d

250C

answer is A.

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Detailed Solution

From Gay – Lussac’s law,   PV=nRT---(1) P+0.4%PV=nRT+1 P+P250V=nRT+1---(2) divide (1) and (2) we get   T=250K
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If a pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 10C, the initial temperature must be