If pressure at half the depth of a lake is equal to 2/3 pressure at the bottom of the lake then what is the depth of the lake
10 m
20 m
60 m
30 m
Pressure at bottom of the lake = P0+hρgPressure at half the depth of a lake =P0+h2ρgAccording to given conditionP0+12hρg=23P0+hρg⇒13P0=16hρg⇒h=2P0ρg=2×105103×10=20 m