If pressure P, velocity V and time T are taken as fundamental physical quantities, the dimensional formula of force is
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a
PV2T2
b
P−1V2T2
c
PVT2
d
P−1VT2
answer is A.
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Detailed Solution
Let F ∝ PxVyTzby substituting the following dimensions:P = ML−1T-2, V = LT−1, T = TMLT-2= [ML−1T-2]x [LT−1]y[T]zand comparing the dimension of both sidesx = 1, y = 2, z = 2, so F = PV2T2