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Questions  

If q is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is 

a
qε0 normal to surface
b
q2ε0 normal to surface
c
qε0 tangential to surface
d
q2ε0 tangential to surface

detailed solution

Correct option is A

Total charge =q×4πr2Electric field intensity on the surface E=14πε0q×4πr2r2=qε0

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