Questions
If q is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is
detailed solution
Correct option is A
Total charge =q×4πr2Electric field intensity on the surface E=14πε0q×4πr2r2=qε0Talk to our academic expert!
Similar Questions
A sphere of radius R has a uniform distribution of electric charge in its volume. At a distance x from its centre, for , the electric field is directly proportional to
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