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Q.

If q  is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is

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a

qε0 normal to surface

b

q2ε0 normal to surface

c

qε0 tangential to surface

d

q2ε0 tangential to surface

answer is A.

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Detailed Solution

Electric field E= qA ε0=qε0     since  qA=q
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