If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is
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a
tan-1(HR)
b
tan-1(2HR)
c
tan-1(4HR)
d
tan-1(4RH)
answer is C.
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Detailed Solution
Maximum height, H = u2sin2θ2g ------(i)Horizontal range, R = u2sin 2 θg = 2u2 sin θ cos θg-------------(ii)Dividing (i) by (ii), we getHR = tan θ4 or tan θ = 4HR or θ = tan-1(4HR)