Questions
If R and H represent horizontal range and maximum height of the projectile, then the angle of projection with the horizontal is
a
tan-1(HR)
b
tan-1(2HR)
c
tan-1(4HR)
d
tan-1(4RH)
detailed solution
Correct option is C
Maximum height, H = u2sin2θ2g ------(i)Horizontal range, R = u2sin 2 θg = 2u2 sin θ cos θg-------------(ii)Dividing (i) by (ii), we getHR = tan θ4 or tan θ = 4HR or θ = tan-1(4HR)Talk to our academic expert!
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A ball is projected obliquely with a velocity 49 ms–1 strikes the ground at a distance of 245 m from the point of projection. It remained in air for
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